python五子棋实验报告_重庆千锋IT培训

python五子棋实验报告

来源：千锋教育

发布人：xqq

时间： 2023-11-16 16:51:18

Python五子棋实验报告

Python五子棋是一种基于Python编程语言的人机对战棋类游戏，其实现过程主要包括棋盘绘制、玩家交互、胜负判断等功能。本次实验旨在通过实现Python五子棋游戏，提高学生对Python语言的掌握能力，同时加深对算法思想的理解。

实验过程

1.棋盘绘制

棋盘绘制是实现Python五子棋游戏的第一步，我们通过使用Python的turtle库，绘制出一个19*19的棋盘。具体实现过程如下：

`python

import turtle

# 绘制棋盘

def draw_board():

turtle.speed(0)

turtle.color("black")

turtle.pensize(2)

turtle.penup()

turtle.goto(-180, 180)

turtle.pendown()

for i in range(19):

turtle.forward(360)

turtle.penup()

turtle.goto(-180, turtle.ycor() - 20)

turtle.pendown()

turtle.right(90)

for i in range(19):

turtle.forward(360)

turtle.penup()

turtle.goto(turtle.xcor() - 20, 180)

turtle.pendown()

turtle.hideturtle()

draw_board()


2.玩家交互
玩家交互是Python五子棋游戏的核心，我们需要实现玩家与计算机的交互，即玩家下棋后，计算机判断胜负并进行相应的反应。具体实现过程如下：
`python
# 判断胜负
def is_win(board, x, y, color):
    count = 1
    # 判断横向
    i = 1
    while x + i < 19 and board[x + i][y] == color:
        count += 1
        i += 1
    i = 1
    while x - i >= 0 and board[x - i][y] == color:
        count += 1
        i += 1
    if count >= 5:
        return True
    # 判断纵向
    count = 1
    i = 1
    while y + i < 19 and board[x][y + i] == color:
        count += 1
        i += 1
    i = 1
    while y - i >= 0 and board[x][y - i] == color:
        count += 1
        i += 1
    if count >= 5:
        return True
    # 判断左上到右下
    count = 1
    i = 1
    while x + i < 19 and y + i < 19 and board[x + i][y + i] == color:
        count += 1
        i += 1
    i = 1
    while x - i >= 0 and y - i >= 0 and board[x - i][y - i] == color:
        count += 1
        i += 1
    if count >= 5:
        return True
    # 判断右上到左下
    count = 1
    i = 1
    while x + i < 19 and y - i >= 0 and board[x + i][y - i] == color:
        count += 1
        i += 1
    i = 1
    while x - i >= 0 and y + i < 19 and board[x - i][y + i] == color:
        count += 1
        i += 1
    if count >= 5:
        return True
    return False
# 玩家下棋
def player_move(board, player_color):
    x, y = turtle.numinput("下棋", "请输入坐标（1-19）：", default=None, minval=1, maxval=19), turtle.numinput("下棋", "请输入坐标（1-19）：", default=None, minval=1, maxval=19)
    x, y = int(x) - 1, int(y) - 1
    if board[x][y] != 0:
        turtle.textinput("提示", "该位置已有棋子，请重新输入。")
        player_move(board, player_color)
    else:
        draw_chess(x, y, player_color)
        board[x][y] = player_color
        if is_win(board, x, y, player_color):
            turtle.textinput("游戏结束", "你赢了！")
            turtle.bye()
        else:
            computer_move(board, 3 - player_color)
# 计算机下棋
def computer_move(board, computer_color):
    x, y = get_computer_move(board, computer_color)
    draw_chess(x, y, computer_color)
    board[x][y] = computer_color
    if is_win(board, x, y, computer_color):
        turtle.textinput("游戏结束", "你输了！")
        turtle.bye()
# 获取计算机下棋位置
def get_computer_move(board, computer_color):
    for i in range(19):
        for j in range(19):
            if board[i][j] == 0:
                board[i][j] = computer_color
                if is_win(board, i, j, computer_color):
                    board[i][j] = 0
                    return i, j
                board[i][j] = 0
    return get_random_move(board, computer_color)
# 获取随机下棋位置
def get_random_move(board, color):
    import random
    x, y = random.randint(0, 18), random.randint(0, 18)
    while board[x][y] != 0:
        x, y = random.randint(0, 18), random.randint(0, 18)
    return x, y
# 绘制棋子
def draw_chess(x, y, color):
    turtle.speed(0)
    turtle.penup()
    turtle.goto(x * 20 - 180, 180 - y * 20)
    turtle.pendown()
    if color == 1:
        turtle.color("black")
    else:
        turtle.color("white")
    turtle.begin_fill()
    turtle.circle(10)
    turtle.end_fill()

3.胜负判断

胜负判断是Python五子棋游戏的最后一步，我们需要在玩家下棋后，判断当前局面是否有胜负。具体实现过程如下：

`python

# 判断胜负

def is_win(board, x, y, color):

count = 1

# 判断横向

i = 1

while x + i < 19 and board[x + i][y] == color:

count += 1

i += 1

i = 1